In MNLP, NP bisects ∠MNL. Is this enough information to prove that MNLP is a rhombus? Explain.
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Mathematics, 27.02.2020 05:01 bae2080
In MNLP, NP bisects ∠MNL. Is this enough information to prove that MNLP is a rhombus? Explain.
A. Yes, by Theorem 6−17
B. Yes, because it proves that MNLP is a rectangle, and any rectangle is also a rhombus.
C. No; you also need to know MNLP is a parallelogram and that ∠MNL is supplementary to ∠PMN.
D. No; you also need to know that MNLP is a parallelogram and that NP bisects ∠LPM.
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