The carbon dioxide emissions of a group of nations had a mean of 8.7 and standard deviation of 2.1. a. One country's observation was 14.1. Find its z-score and interpret. b. Another country's observation was 2.2. Find its z-score and interpret. c. A third country's observation was 9.1. Find its z-score and interpret.

a)

This country emmits 2.57 standard deviations above the mean of the emissions of the countries of this group of nations.

b)

This country emmits 3.1 standard deviations below the mean of the emissions of the countries of this group of nations.

c)

This country emmits 0.19 standard deviations above the mean of the emissions of the countries of this group of nations.

Step-by-step explanation:

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

a. One country's observation was 14.1. Find its z-score and interpret.

Here we have

This country emmits 2.57 standard deviations above the mean of the emissions of the countries of this group of nations.

b. Another country's observation was 2.2. Find its z-score and interpret.

Here we have

This country emmits 3.1 standard deviations below the mean of the emissions of the countries of this group of nations.

c. A third country's observation was 9.1. Find its z-score and interpret.

Here we have

This country emmits 0.19 standard deviations above the mean of the emissions of the countries of this group of nations.

144.50

step-by-step explanation:

21.5 x 13.4=288.10 divide by 2