Mrs. Sanders had 80 coins. Some of them were 1-dollar coins, and the rest were 50-cent coins. The total amount addded up to $50. How many coins of each kind were there?

Since x=20, y=60

We have 20 1-dollar coins and 60 50-cent coins

Step-by-step explanation:

Let the number of 1-dollar coins =x

Let the number of 50-cent coins =y

Mrs.Sanders had 80 coins

Therefore: x+y=80 (i)

The total amount added up to $50

Therefore: 1x+0.50y=50 (ii)

From equation (i), x=80-y

Substituting x=80-y into equation (ii)

1x+0.50y=50

80-y+0.50y=50

80-50=y-0.5y

30=0.5y

y=30/0.5=60

From (i)

x+y=80

x+60=80

x=80-60=20

x=20, y=60

answer 1 : option "c"

answer 2 : option "d"

answer 3 : option "b"

answer 4 : option "d"

answer 5 : option "b"

answer 6 : option "a"

answer 7 : option "c"

answer 8 : option "d"

answer 9 : option "c"

answer 10 : option "d"

answer 11 : option "c"

answer 12 option "b"

answer 13 option "c"

answer 14 option "c"

answer 15 option "d"

answer 16 option "a"

answer 17 option "b"

answer 18 option "c"

answer 19 option "a"

answer 20 option "a"

answer 21 option "c"

d

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol