Mathematics, 27.02.2020 01:24 landonp101

Xfavor algien que me ayude la pregunta 5.6 .7 .8 es de urgencia
por favor chicos

Xfavor algien que me ayude la pregunta 5.6 .7 .8 es de urgenciapor favor chicos

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Answer from: ItzMeEmilyyyy

Part 5) The maximum value of z is 110.7

Part 6) The maximum value of z is 6

Part 7) The minimum value of z is 120

Part 8 The minimum value of z is 3

Step-by-step explanation:

Part 5) Maximizes function z subject to constraints

z=5x+7y

$2x+3y\leq 45$ ----> constraints A

$x-3y\leq 2$ ---> constraints B

$x\geq 0$ ---> constraints C

$y\geq 0$ ---> constraints D

using a graphing tool

The solution is the shaded area

The vertices of the shaded area are

(0,0),(2,0),(15.7,4.6) and (0,15)

see the attached figure N 1

Substitute the value of x and the value of y of each vertex in the objective function z and then compare the results

For (0,0) ----> z=5(0)+7(0)=0

For (2,0) ----> z=5(2)+7(0)=10

For (15.7,4.6) ----> z=5(15.7)+7(4.6)=110.7

For (0,17) ----> z=5(0)+7(15)=105

therefore

The maximum value of z is 110.7

Part 6) Maximizes function z subject to constraints

z=2x+y

$y\leq x+2$ ----> constraints A

$y\leq -x+3$ ---> constraints B

$x\geq 0$ ---> constraints C

$y\geq 0$ ---> constraints D

using a graphing tool

The solution is the shaded area

The vertices of the shaded area are

(0,0),(3,0),(0.5,2.5) and (0,2)

see the attached figure N 2

Substitute the value of x and the value of y of each vertex in the objective function z and then compare the results

For (0,0) ----> z=2(0)+(0)=0

For (3,0) ----> z=2(3)+(0)=6

For (0.5,2.5) ----> z=2(0.5)+(2.5)=3.5

For (0,2) ----> z=2(0)+(2)=2

therefore

The maximum value of z is 6

Part 7) Minimize function z subject to constraints

z=2x+2y

$x+2y\geq 80$ ----> constraints A

$3x+2y\geq 160$ ---> constraints B

$5x+2y\geq 200$ --> constraints C

$x\geq 0$ ---> constraints D

$y\geq 0$ ---> constraints E

using a graphing tool

The solution is the shaded area

The vertices of the shaded area are

(0,100),(20,50),(40,20) and (80,0)

see the attached figure N 3

Substitute the value of x and the value of y of each vertex in the objective function z and then compare the results

For (0,100) ----> z=2(0)+2(100)=200

For (20,50) ----> z=2(20)+2(50)=140

For (40,20) ----> z=2(40)+2(20)=120

For (80,0) ----> z=2(80)+2(0)=160

therefore

The minimum value of z is 120

Part 8) Minimize function z subject to constraints

z=7x+3y

$3x-y\geq -2$ ----> constraints A

$x+y\leq 9$ ---> constraints B

x-y=-1 --> constraints C

$x\geq 0$ ---> constraints D

$y\geq 0$ ---> constraints E

using a graphing tool

The solution is the line segment (0,1) to (4,5)

see the attached figure N 4

Substitute the value of x and the value of y of each endpoint in the objective function z and then compare the results

For (0,1) ----> z=7(0)+3(1)=3

For (4,5) ----> z=7(4)+3(5)=43

therefore

The minimum value of z is 3

Xfavor algien que me ayude la pregunta 5.6 .7 .8 es de urgenciapor favor chicos

Answer from: Quest

9987

step-by-step explanation:

Answer from: Quest

That is right sorry i was gonna answer but i already saw his

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