How do I solve #4 a-c?

Step-by-step explanation:

4a) By repeating the error pattern found in the previous examples, the last example would be 638

4b) Looking at the examples, the multiplication was wrongly done. In multiplying, the unit term was multiplied first. This is right. The error was that the tens term was not added to the product of the multiplier and the tens term. The remainder was neglected.

c) the student should always add the tens from the product of the unit term and the multiplier to the product of the tens term and the multiplier. For example, the first one would be

8 × 6 = 48

You put down 8 and add 4(tens term) to the product of the tens term and the multiplier(4 + 8×3 = 28)

The solution becomes 288

3-4

step-by-step explanation:

the answer is 3-4 because both 45 and 60 has a multiple of 15.

45/3=15

60/4=15

therefore the odds against selecting a red is 4-3

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.