Jose surveyed the length of TV commercials (in seconds). Find, to 3 decimal places, the experimental probability that a randomly chosen TV commercial will last:

≈0.487

Step-by-step explanation:

I think this is your full question right?

Jose surveyed the length of TV commercials (in seconds). Find, to 3 decimal places, the experimental probability that a randomly chosen TV commercial will last:

Length        Frequency

0-19                   17

20-39               38

40-59                19                    20 to 39 seconds.

60+ 20 to          4

Here is my anwer:

experimental probability = relative frequency =

Total frequencies = 17 + 38 +18 + 4 = 78

P(20 to 39s) = 38/78 ≈0.487  

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1