What is the standard form equation of the line shown below? Graph of a line going through negative 2, 3 and 1, negative 3

1. y + 3 = −2(x − 1)
2. y = −2x − 1
3. 2x + y = −1
4. −2x − y = 1

3. 2x + y = −1

Step-by-step explanation:

To find the equation of the line, we write it first in the slope-intercept form:

where

m is the slope

q is the y-intercept

From the graph, we see that the line crosses the y-axis at y = -1, so the y-intercept is -1:

Now we have to find the slope, by calculating the rate of change of the line through 2 points:

Taking the two points at (-2,3) and (1,-3), we find:

So the equation of the line is

Now we have to re-arrange it in the standard form, so in the form

where a, b and c are integer numbers.

To do that, we simply add +2x on both sides of the equation of the line in the slope-intercept form, and we get:

So, option 3).

answer: i'm great at algebra

~coco

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)