The circumference of the inner circle is 66 ft. The distance between the inner circle and the outer circle is 44 ft. By how many feet is the circumference of outer circle greater than the circumference of the inner circle? Use 22/7 for PI.

  276 4/7 ft

Step-by-step explanation:

Let r1 represent the radius of the inner circle. Then its circumference in feet is ...

  C = 2πr

  66 = 2π(r1)

If the radius of the outer circle is (r1 +44), then its circumference is ...

  C = 2π(r1 +44) = 2π(r1) +2π(44)

  C = 66 +88π

Then the difference in the circumferences is ...

  (66 +88π) - (66) = 88π

Using the given value of π, the difference in circumferences is ...

  (88 ft)(22/7) = 1936/7 ft = 276 4/7 ft

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40