1. In the cone below, the radius is 6 meters and the height is 8 meters.
2. Find the volume of the cylinder pictured below. Use 3.14 for pi. Give your answer rounded to the nearest tenth.
3. Find the volume of the sphere pictured below. The sphere has a radius of 20 cm. Use 3.14 for pi. Give your
answer rounded to the nearest tenth.
A) Find the exact value of the volume of the cone.
formula V =
Pug in #s V =
solution with a label V =
B) Find the approximate value of the volume of the cone rounded to the
nearest tenth.
formula V =
Pug in #s V =
solution with a label V =

*NEED ANSWER BY 5:00 PM TONIGHT PLEASE!*

1a)Exact volume= 301.5928947m³

1b)Approximate volume = 301.6 m³

2)Volume of cylinder = 904.7808 m³

3)Volume of sphere = 0.0335104 m³

Step-by-step explanation:

1). A) exact value of volume of cone

Volume of cone =(1/3)(π)(r²)(h)

Exact volume= (1/3)(3.1416)(6²)(8)

Exact volume= 301.5928947m³

1).B). Approximate value of the cone to the nearest tenth

Approximate volume = 301.6 m³

2) volume of cylinder = (π)(r²)(h)

Volume = (3.1416)(6²)(8)

Volume = 904.7808 m³

3). Volume of sphere = 4/3πr³

20cm = 0.2m

Volume = (4/3)((3.1416)(0.2³)

Volume = 0.0335104 m³

maya’s expression will generate the wrong sum because she violated the commutative property.

step-by-step explanation:

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.