How do you find the angles on this special triangle?

Well this is simple. First you have to know what type of formula your gonna be using. Which means you can’t use a squared+b squared=c squared.
So first you look for what angles you do have and that’s a 90 degree angle. Next you look for other givens like the two side are even. Now you know it’s a Isosceles triangle. So since we know we have 90 degree angel already and there can only be 90 left becasue it’s only 180 degrees in a triangle and 90+90 makes 180. You divid 90 by 2 and it gives you 45 and that’s the other two angles. Anther name for the triangle is 45,45,90 it’s called for special triangles when using square root.

Ibelieve the answer is b. y=0 would make the line horizontal across the x.