A rectangles length is 2 in more than its width. The area of the rectangle is 143 square inches. Find the dimensions of the rectangle.

The length is 13 inches and the width is 11 inches.

Step-by-step explanation:

Let L represent the length of the rectangle.

Let W represent the width of the rectangle.

The formula for determining the area of a rectangle is expressed as

Area = LW

The area of the rectangle is 143 square inches. This means that

LW = 143 - - - - - - - - - - - - --1

The rectangle's length is 2 in more than its width. This means that

L = W + 2

Substituting L = W + 2 into equation 1, it becomes

W(W + 2) = 143

W² + 2W - 143 = 0

W² + 13W - 11W - 143 = 0

W(W + 13) - 11(W + 13) = 0

W + 13 = 0 or W - 11 = 0

W = - 13 or W = 11

Since the width cannot be negative, it means that W = 11

L = W + 2 = 11 + 2

L = 13

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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