Let f={(-2,4),(-1,2)(0,0)(1,-2),(2,5)}. let g ={(-33),(-1,1),(0,-3)(1,-4)(3,-6)}. What is g(f(2))?

g(f(2)) does not exist if

g={(-3,3),(-1,1),(0,-3),(1,-4),(3,-6)} and f={(-2,4),(-1,2),(0,0),(1,-2),(2,5)}.

Step-by-step explanation:

Hi. Welcome to .

When finding g(f(2)), you must compute f(2) first.

Looking at f={(-2,4),(-1,2),(0,0),(1,-2),(2,5)}, we see that the ordered pair (2,5) is contained within the set defined as the set f. This means f(2)=5.

So now we have g(f(2))=g(5).

We now need to look at our set named g, g={(-3,3),(-1,1),(0,-3),(1,-4),(3,-6)}. We see the the no ordered pair looks like (5,something). The only conclusion is that g(f(2)) does not exist.

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step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet