Consider the points below. P(1, 3, 5), Q(−4, 7, 3), R(2, 2, 6)

(a) Find a nonzero vector orthogonal to the plane through the points P, Q, and R.
(b) Find the area of the triangle PQR.

a. <2,3,1>

b.

Step-by-step explanation:

From the data given, we have point

P(1,3,5)

Q(-4,7,3)

R(2,2,6)

a. For us to find a vector orthogonal to the plane through the points P,Q and R we define two vectors such as

PQ=<-4,7,3>-<1,3,5>

PQ=<-5,4,-2>

we also define PR

PR=<2,2,6>-<1,3,5>

PR=<1,-1,1>

The cross product of the two formed vector gives rise to a vector that is orthogonal to the given plane Hence we carry out the cross product

Hence the required vector is <2,3,1>

b. The area of the formed triangle can be expressed as

i think 5 miles per hour

step-by-step explanation:

answer: y=4000x+14000

step-by-step explanation: