Let f be a continuous function on the closed interval [ − 2 , 5 ]. If f((-2)=-7 and f(5)=1, then the Intermediate Value Theorem guarantees that

The function has at least 1 zero within the interval [-2,5].

Step-by-step explanation:

The intermediate value theorem states that, for a function continuous in a certain interval , then the function takes any value between and at some point within that interval.

This theorem has an important consequence:

If a function is continuous in an interval [a,b], and the sign of the function changes at the extreme points of the interval:

(or viceversa)

Then the function f(x) has at least one zero within the interval [a,b].

We can apply the theorem to this case. In fact, here we have a function f(x) continuous within the interval

[-2,5]

And we also know that the function changes sign at the extreme points of the interval:

Therefore, the function has at least 1 zero within the interval [-2,5], so there is at least one point x' within this interval such that

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

correct answer is option b.

step-by-step explanation:

the true statement about geometric figure is option b that is one line can be drawn through all three points.

if three points are on the same plane, they can be connected by a line.