A company produces widgets in three factories, A, B and C. Factory A produces 20% of the widgets, factory B produces 45% of the widgets and factory C produces the remaining 35%. Of all widgets produced, 5% fail tolerance. Of those that fail tolerance, 25% were produced in factory A, 35% were produced in factory B and 40% were produced in factory C.
In factory A, what percentage of the widgets produced fails tolerance?

1.25% widgets from factory A fail.

Step-by-step explanation:

Probability of widgets that fail = 0.05

Probability of failing widget to belong from factory A = 0.25

Probability of failing widget to belong from factory B = 0.35

Probability of failing widget to belong from factory C = 0.40

Probability of factory A widgets failing = Probability of widgets failing * probability they belonged from factory A

Probability of factory A widgets failing = 0.05 * 0.25 = 0.0125

This probability stated as percentage: 1.25%

we'll this would mean that the dunk tank and the bounce house are the same for 20 hours because the 2 represents that the two activities, and the 20 represents the amount of hours they both are. so with this said, it means that the answer is c. the costs for a dunk tank and bounce house are the same for 20 hours.

c.the costs for a dunk tank and bounce house are the same for 20 hours.

hope this .

2x^2+5x+17

your welcome. : )