The function A(s) given by A(s)equals0.328splus50 can be used to estimate the average age of employees of a company in the years 1981 to 2009. Let A(s) be the average age of an employee, and s be the number of years since 1981; that is, sequals0 for 1981 and sequals9 for 1990. What was the average age of the employees in 2003 and in 2009?

Step-by-step explanation:

We are given the function A(s) as;

           A(s) = 0.328*s + 50   where s = number of years since 1981; that is,

                                                   s = 0 for 1981 and s = 9 for 1990

A(s) = the average age of an employee

        Here s = 22 because 2003 - 1981 = 22 years

Therefore, average age of the employees in 2003 = 7.216 + 50 = 57.216 .

        Here, s = 28 because 2009 - 1981 = 28 years

Therefore, average age of the employees in 2009 = 9.184 + 50 = 59.184 .

a4 - 3a2 - 1

step-by-step explanation:

step   1   :

equation at the end of step   1   :

  ((a4) -   3a2) -   1

step   2   :

trying to factor by splitting the middle term

2.1     factoring   a4-3a2-1  

the first term is,   a4   its coefficient is   1 .

the middle term is,   -3a2   its coefficient is   -3 .

the last term, "the constant", is   -1