A factory manager collected data on the number of breakdowns per day. From these data, he derived the probability distribution for X, the number of breakdowns on a given day:

X 0 1 2
prob 0.80 0.15 0.05

1)The mean of X is (exact answer)

2)The standard deviation of X is (to three places after the decimal)

3)On average, how many breakdowns are there per day?

4)Assuming there are weekend shifts in the factory (work goes on every day), about how many breakdowns are expected during a one-year period. (non-leap year, and round to the nearest whole number).

a) 0.25

b) 0.536

c) 0.25

d) 91

Step-by-step explanation:

We are given the following in the question:

X:         0         1          2

P(x) : 0.80     0.15    0.05

a) The mean of X

b) The standard deviation of X

c) breakdowns are there per day

On average, there are 0.25 breakdowns per day.

d) breakdowns are expected during a one-year period

Thus, there are approximately 91 breakdowns during a one-year period.

1e+27

step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: