The frequency of a vibrating guitar
string varies inversely as its length.
Suppose a guitar string 0.65 meters long
vibrates 4.3 times per second. What
frequency would a string 0.5 meters long
have?

5.59 per seconds

Step-by-step explanation:

F is inversely proportional to L i.e

F & 1/L

F = K/L

FL = K

But F = 4.3, L = 0.65

K = FL = 4.3 x 0.65

K = 2.795

Now, we can find F when L = 0.5 by doing the following:

F = K/L

F = 2.795/0.5

F = 5.59 per seconds

faster, im not sure why but i know it is faster

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.