What are the dimensions to maximize the area of a rectangular horse pen with 200 feet of fencing if the north side of the pen uses the side of the barn?

The dimensions to maximize the area is 50 by 100

Step-by-step explanation:

Let x= the length of the side perpendicular to the barn 

and 200-2x= length of the side parallel to the barn

Area = x(200-2x) (1)

Area =-+200x

The formula for the w-value of maximum is: -b/2a

thus our value will be:

200/4 =50

and substitue x = 50 into (1), we have:  200-2(20) =100

Thus the dimensions to maximize the area is 50 by 100

d

because parallelagram have all 4 angels the same size dependeing and a rectangle and square are oth parallelogram

i think it would be c

mark brainliest if im right

step-by-step explanation: