I need help with my 9 th grade paper

(1)   3.81470 • 10^-6

(2)  4.76837 • 10^-7

(3)  0.33333

(4)  2^8

(5) 7^5

(6) (23•33)

(7) 2^3

(8) 0.01235

(9)  1

(10) 0.00002

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1 is 262144

2 is 2097152

3 is 3

4 is 256

5 is 16807

6 is 216

7 is 8

8 is 81

9 is 1

10 is 65536

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240