Help me please i need help in this math assignment please i will give points

if the discriminant < 0 no solution

if = 0 then one solution

if > 0 then two solutions

start from the first one and calculate b^2-4ac

the first one is x^2 + 4x +4 = 0

a is the factor next to x^2 (1 in this case)

b is the factor next to x (4 in this case)

c is the number without any x (4 in this case)

so the discriminant is 4^2 - 4*(1)*4 = 16-16 = 0 = one solution

Step-by-step explanation:

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

your answer would be b