A twelve-sided die with sides labeled 1 through 12 will be rolled once. Each number is equally likely to be rolled. What is the probability of rolling a number greater than 4?

The probability of rolling a number greater than 4 is 2/3

Step-by-step explanation:

There are 8 numbers that are > 4 and ≤ 12

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12.

So put a fraction of the desired process by the total outcome.

8/12 = 2/3

2/3

Step-by-step explanation:

Probability= desired number of outcome/possible outcome

If you roll a single die there are 12 possible outcomes (1,2,3,4,5,6,7,8,9,10,11,13), 8 of these numbers are greater than 4.

In a single roll the probability of getting a number greater than 4 is 8/12 = 2/3

the answer would be c:   ax + b = ax + c

step-by-step explanation:

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."