Pls help geo/trig

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 59°. Building A is 40 feet away, and building B is 60 feet away. Which building is taller and by approximately how many feet?

Building A; it is around 66.57 feet taller than building B
Building A; it is around 33.29 feet taller than building B
Building B; it is around 66.57 feet taller than building A
Building B; it is around 33.29 feet taller than building A

Solution:

Given that,

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 59°

Building A is 40 feet away, and building B is 60 feet away

This forms a right angled triangle

height of building is the perpendicular

Distance between kayson and building forms the base ( adjacent)

If the height of the building A is x feet, then

Thus, height of building A is 66.57 feet

Building B is 60 feet away

If the height of building is y feet,

Thus, building B is taller

Building B - building A = 99.86 - 66.57 = 33.29 feet

Thus building B is taller and it is around 33.29 feet taller than building A

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation:

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation: