How much wrapping paper will be needed to cover the figure below rounded to the
nearest tenth? HELP ASAP

125.9 cm^2
76 cm ^2
180 cm^2
100.1 cm^2

125.9 cm^2

Step-by-step explanation:

Since the box will be covered all around we need to find the area of the figure

Tthe formula to calculate area of a cuboid is : 2 (lw + wh + hl)  (l: length, w: width, h: height)

2 × (2.2×9.1 + 2.2×3.8 + 9.1×3.8) = 125.9 cm^2

Step-by-step explanation:

the data we have is

height = 2.2cm

long = 9.1cm

width = 3.8cm

the area of the top and bottom is given by:

since we need both the top and the bottom covered we multiply by 2:

Now for the area of the front and back:

and also since we need both front and back we multiply by 2:

the area for the sides:

and we multiply by 2 to get both sides:

and finally we add all the areas:

the amount of wrapping paper needed is

coins of silver or gold

step-by-step explanation:

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !