![\frac{ {8}^{ \frac{1}{3} } }{ {5}^{ - 2} } = \frac{ \sqrt[3]{ {8}^{1} } }{ \frac{1}{ {5}^{2} } } = \frac{ \sqrt[3]{ {2}^{3} } }{ \frac{1}{ {5}^{2} } } = \frac{2}{ \frac{1}{25} } = 2 \times 25 = 50](/tpl/images/0521/9536/31708.png)
![{8}^{ \frac{a}{b} } = \sqrt[b]{ {8}^{a} }](/tpl/images/0521/9536/2f75c.png)
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Mathematics, 24.02.2020 22:42 thedocgalloway
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