Computer battery A has 4/5 of its power remaining. Computer battery B has 9/20 of its power remaining. How much more power does computer battery A have compared to computer battery B?

7/20

Step-by-step explanation:

GIven:

Battery A = 4/5 remaining

Battery B = 9/20 remaining

assuming both batteries are otherwise identical (except for charge level remaining), then,

Battery A - Battery B

= 4/5 - 9/20

we need to convert both fractions to same denominator to perform the subtraction easily. Note that the Least Common Multiple for 5 and 20 is 20, hence we convert both denominators to 20,

Battery A - Battery B

= 4/5 - 9/20

= (4/5) (4/4) - 9/20

= 16/20-9/20

= 7/20

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.