You want to determine the probability that in a family of 5 children, there will be more girls than boys. Which describes one trial of a simulation you could use to model this problem?

A.
Toss a coin 5 times and count the number of heads.

B.
Toss a 6-sided number cube 5 times and count the number of times you get a number less than 3.

C.
Generate 5 random numbers between 0 and 100 and count the number of prime numbers.

D.
Draw 5 cards at random from a standard 52-card deck, replacing each card after it is drawn and count the number of hearts. ( There are an equal number of hearts, spades, diamonds, and clubs in a deck.)

A

Step-by-step explanation:

The answer is A because since there's only two genders and a coin has two sides a gender can represent a side.

A makes the most sense since the others have multiple different sides that you could get for example B has a six sided number cube that's more than the number of genders so A makes the most sense

step-by-step explanation:

their are no angles. sorry cant .

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3