Two crossroads, each of width 5 m, run at right angles through the centre of
a rectangular park of length 70 m, breadth 45 m and parallel to its sides. Find
the area of the crossroads.

550 sq m

Step-by-step explanation:

Step 1 :

The length of the first cross road the park  is 70 m

The width of the first cross road the park  is 5 m

So its area is 70 * 5  = 350 sq m

Step 2 :

The length of the second cross road the park  is 45 m

The width of the width cross road the park  is 5 m

So its area is 45 * 5 = 225 sq m

Step 3 :

The 2 cross roads intersect in the middle at an area of 5 * 5 = 25 sq m

This area is included in the computation of the area of both the cross roads and hence we need to subtract this area from the sum of the area of both the cross roads to obtain the actual area of cross roads in the park

So we have

the area of the cross roads inside the park = 350 + 225 - 25 = 550 sq m

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation: