ᒍEᑎᔕ GOᗩᒪ Iᔕ TO ᖇᑌᑎ ᗩ TOTᗩᒪ Oᖴ 22 ᗰIᒪEᔕ Iᑎ ᖴIᐯE ᗪᗩYᔕ. TᕼE TᗩᗷᒪE ᗷEᒪOᗯ ᔕᕼOᗯᔕ ᕼEᖇ ᒪOG ᖴOᖇ TᕼE ᑎᑌᗰᗷEᖇ Oᖴ ᗰIᒪEᔕ ᔕᕼE ᖇᗩᑎ Oᑎ ᗰOᑎᗪᗩY, TᑌEᔕᗪᗩY,ᗯEᑎᗪᔕᗩᗪY,ᗩᑎᗪ TᕼᑌᖇᔕᗪᗩY ᕼOᗯ ᗰᗩᑎY ᗰIᒪEᔕ ᗰᑌᔕT ᒍEᑎ ᖇᑌᑎ Oᑎ ᖴᖇIᗪᗩY TO ᖇEᗩᑕᕼ ᕼEᖇ GOᗩᒪ

3

step-by-step explanation:

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

what

answer4 to the second power is 16

and 4 to the third power is 64,