One hundred students took a statistics mid term exam the scores formed a normal distribution with a mean of 84 and a standard deviation of 6 Lucille took the exam but received a 78 on it. What was her approximate percentile tank

The percentile of Lucile is 15%.

Step-by-step explanation:

As per given data

Mean=μ=84

Standard Deviation=σ=6

Marks of Lucille=X=78

So the percentile for the normal distribution is given as

For this the Z value is calculated as

For the Z value of -1, from the Z table the value of P is found as

P(X<78)=P(Z<-1)=0.1587=15.87%

So the percentile of Lucile is 15%.

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

i dont understand the question? ?

step-by-step explanation: