*A triangle has sides 42, 4x, and 2x−6. What is the possible range of x?

Step-by-step explanation:

To can draw this triangle if:

4x - (2x - 6) < 42 < 4x + (2x - 6)

solve inequality 1 :

4x - (2x - 6) < 42 ⇔ 2x + 6 < 42 ⇔ 2x < 36 ⇔ x < 18 (1)

Solve inequality 2 :

42 < 4x + (2x - 6) ⇔ 42 < 6x - 6 ⇔ 48 < 6x ⇔ 8 < x (2)

from (1) and (2) we deduce that : 8 < x < 18

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)