Prove that in a right angle triangle-- AC2 = AB2 + BC2

AC^2=AB^2+BC^2

Step-by-step explanation:

Given information: In triangle ABC, ∠B=90°.

To prove: AC^2=AB^2+BC^2

Proof:

According to the Pythagoras theorem, in a right angled triangle

hypotenuse^2=perpendicular^2+base^2

Since ∠B=90°, it means ABC is right angled triangle, AC is hypotenuse, AB and BC are two legs.

Using Pythagoras theorem we get

AC^2=AB^2+BC^2

Hence proved.

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step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}