The function f(x) is a cubic function and the zeros of f(x) are -6, -3 and 1. Assume the leading coefficient of f(x) is 1. Write the equation of the cubic polynomial in standard form.

f(x) = x³+8x²+9x-18

Step-by-step explanation:

Factors are: (x+6)(x+3)(x-1)

= (x+6)(x²+3x-x-3)

= (x+6)(x²+2x-3)

= x³+2x²-3x+6x²+12x-18

f(x) = x³+8x²+9x-18

Step-by-step explanation:

If is a zero of , then is a factor of .

Since -6,-3, and 1 are zeros, then we have the following factors of :

, , and .

Let's put it together.

, where is the leading coefficient and we are given to make it equal to 1, has zeros -6,-3, and 1.

We now need to put the factored form of into standard form by using multiplication and combining of like terms.

answer:

c) the x-coordinate of the center of the circle increases by 3