What is the solution to 2х2+8х=х2-16?

double, real root x = -4

Step-by-step explanation:

Please use " ^ " to indicate exponentation:  2х^2 + 8х = х^2 - 16.

Combine like terms:

х^2 + 8х = - 16.

Re-write in the standard form for a quadratic:

х^2 + 8х + 16 = 0

Recognize that this is the square of the binomial x + 4:

х^2 + 8х + 16 = 0  =>  (x + 4)^2 = 0

Solving this last result for x yields the double, real root x = -4.

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answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11