Ling lives 2 miles from school. It took him 15 minutes to bike from school to home. The first half of the distance he biked at a speed of 12 mph. What was his speed for the remaining distance? What was his average speed?
His speed for remaining distance was (NEED1) mph and his average speed was
(NEED2) mph.

a) time = distance/speed

For the first half of the trip, the time used was

.. (1 mi)/(12 mi/h) = (1/12) h = 5 minutes

Then the last half of the trip took 10 minutes, 1/6 hour.

.. speed = distance/time

.. = (1 mi)/(1/6 h) = 6 mi/h

The speed for the last half of the trip was 6 mph.

b) The average speed was

.. (2 mi)/(1/4 h) = 8 mi/h

Ling's average speed was 8 mph.

hope this helps if so plz mark the brainliest

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

i think it might be a but you might want a second opinion