Ten is the average number of oil tankers arriving each day at a certain port city. The facilities can handle at most 15 tankers per day. What is the probability that on a given day, tankers will have to be turned away?

The probability of more than 15 tankers arrival is = P = 0.0487 = 4.8 %

Step-by-step explanation:

The poisson probability will be used to solve this question.

Let the probability of arriving k tankers = P (k) = e^-λ x (λ ^k / k!)

Where λ = average number of tankers arriving today.

Now calculating this equation through a spread sheet and taking sum of all 15 values,

P(k) = 0.9513

therefore

P (>15) = 1 - P(k)

P (>15) = 1 - 0.9513

P (>15) = 0.0487

P (>15) = 48 %

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!