At 6 a. m., the temperature is 19.4°C. Between 6 a. m. and noon, the temperature rises 3.8°C. Between noon and 6 p. m., the temperature falls 2.5°C.

How much greater is the temperature at 6 p. m. than it was at 6 a. m.?

The difference will be 1.3°C

First given temperature = 19.4°C

The final temperature by 6pm will be:

= 19.4°C + 3.8°C - 2.5°C

= 20.7°C

Now, the difference between the temperature from 6a.m to 6p.m will be:

= 20.7°C - 19.4°C

= 1.3°C

Therefore, the difference is 1.3°C.

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20.7 degrees C

Step-by-step explanation:

Here's the easiest way to solve. Grab a calculator, or a piece of paper. (its simple math) S, The start is 19.4. Then, it rises 3.8. So add that to 19.4. That gives you 23.2, BuT, it falls again, back down 2.5 degrees. so take 23.2, and subtract 2.5 from it. That should give you 20.7 degrees.

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answer: i think it's a

step-by-step explanation:

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.