The hookworm, Necator americanus, which infects some 900 million people worldwide, may ingest more than 0.5 ml of human host blood daily. Given that an infection may number more than 1,000 individual hookworms, calculate the total volume of host blood that may be lost per day to a severe nematode infection.

Minimum of 450million mL per day

Step-by-step explanation:

Given that the hookworm has infested 900 million people with each hookworm investing 0.5 mL per day and for an infested human or infection, you have a minimum of 1000 hookworm injesting blood.

The total number of blood injested by hookworm or lost from human per day is give by

1000hookworm per human×900000000human×0.5mL perday= 450 million blood lost per day

i need a picure

step-by-step explanation:

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.