. A survey found that women spend on average $146 on beauty products during the summer months. Assume the standard deviation is $28. Find the percentage of women who spend less than $160.00. Assume the variable is normally distributed.

69.2%

Step-by-step explanation:

Assuming that the amount that women spend on beauty products during the summer months is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = amount spent.

µ = mean

σ = standard deviation

From the information given,

µ = $146

σ = $28

The probability of women who spend less than $160.00 is expressed as

P(x < 41)

For x = 160

z = (160 - 146)/28= 0.5

Looking at the normal distribution table, the probability corresponding to the z score is 0.6915

Therefore, the percentage of women who spend less than $160.00 is

0.6915 × 100 = 69.2%

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.