Mathematics, 21.02.2020 01:16 victoriay3

In the cube shown below, the distance between vertices 2 and 6 is 17 cm.

If the cube is divided into two equal parts by a plane parallel to the face defined by vertices 2, 3, 6, and 7, what will be the area of the cross-section?

Answers: 2

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In the cube shown below, the distance between vertices 2 and 6 is 17 cm.

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In the cube shown below, the distance between vertices 2 and 6 is 17 cm. If the cube is divided into two equal parts by a plane parallel to the face defined by vertices 2, 3, 6, and 7, what will be the area of the cross-section?

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In the cube shown below, the distance between vertices 2 and 6 is 17 cm.

If the cube is divided into two equal parts by a plane parallel to the face defined by vertices 2, 3, 6, and 7, what will be the area of the cross-section?