Given that the acceleration vector is a(t)=(−1cos(1t))i+(−1sin(1t))j+(3t) k, the initial velocity is v(0)=i+k, and the initial position vector is r(0)=i+j+k, compute:

The Velocity Vector v(t): _ i + _ j +_k

The position vector r(t): _i + _ j + _k

Note: the coefficients in your answers must be entered in the form of expressions in the variable \emph{t};

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