Which of the following integrals correctly computes the volume formed when the region bounded by the curves x2 + y2 = 25, x = 3, and y = 0 is rotated around the y-axis?

The correct integral is    ⇒ 2nd answer

Step-by-step explanation:

The formula of the volume of a curve y = f(x) by integration around the y-axis is  

∵ The curves are x² + y² = 25 , x = 3 and y = 0

- Lets find x in terms of y in the first curve

∵ x² + y² = 25

- Subtract y² from both sides

∴ x² = 25 - y²

- Take square root for both sides

∴ x =

To find the limit of the integration b substitute x by 3

∵ x = 3

∵ x² + y² = 25

∴ 3² + y² = 25

∴ 9 + y² = 25

- Subtract 9 from both sides

∴ y² = 16

- Take square root for both sides

∴ y = ± 4

∵ The 1st limit a is at y = 0

∴ a = 0

∵ The 2nd limit is b at y = 4

∴ b = 4

∴ b = 4

There are two curves x = 3 and x =

To find the volume integrate the difference of the squares of the equations of the two curves and multiply the difference by π

∵    

- Subtract square 3 from the square of      

∴       

The correct integral is        

your answer is b ^w^ hope i

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.