If Cody is draining his hot tub which holds 1,400 gallons of water at a rate of 27 gallons a minute, what impact will it have on the amount of water in the hot tub after
18 minutes?

A) -486 gallons
B) -459 gallons
C) 459 gallons
D) 486 gallons

Facts:

- tub has 1400 gallons

- draining at 27 gallons/minute

How much water will be left after 18 minutes?

We know that after 1 minute, there will be 27 gallons less.

So after 18 minutes, there must be 18 times less water.

27 x 18 = 486

This is how much water was lost in 18 min

So to find out how much he had left after 486 is subtracted.

Therefore, the answer is A) -486 gallons

y=mx+

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2