Bobby and Rick are in a 12-lap race on a one mile oval trac. Bobby, averaging 86mph, has completed two laps just as rick is getting his car onto the track. What speed does Rick have to average to be even with Bobby at the end of the twelve lap?

98.4 mph

Step-by-step explanation:

Bobby has 10 miles to go, speed 82 mph, so the time is 10/82 hours.

Rick has 12 miles to go and has to do it in 10/82 hr

Speed is 12/(10/82)

i.e 12÷10/82 = 12× 82/10

=984/10 = 98.4 mph

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

b is the answer that makes most sense

step-by-step explanation: