E) 65 S Enem) José. Carlos e Paulo devem transportar suas bicicletas com certa quantidade de laranjas. Decidir dividir ou rastrear um ser percorrido em duas partes, sendo o final da primeira parte, redistribua uma quantidade de laranjas que cada um carrega dependendo do cansaço de cada um. Na primeira parte do transporte José. Carlos e Paulo dividiram como laranjas na proporção 6: 5: 4. respectivamente. Na segunda parte do trajeto José. Carlos e Paulo dividiram como laranjas na proporção 4: 4: 2. respectivamente. Sabendo-se que um deles levou 50 laranjas a mais sem segundo, qual a quantidade de laranjas que José, Carlos e Paulo, nessa ordem, transportou na segunda parte do esforço? 8. a) 600, 550, 350. b) 300, 300, 150. c) 300, 250, 200. d) 200, 200, 100. e) 100, 100, 50.

answer:

d

Step-by-step explanation:

total amount of money that he should pay if he has not used his duty free exemption is $98

step-by-step explanation:

given a united states citizen returning to the states declares the following items at the customs office: 3 shirts at $8.50 each 2 dresses at $27.50 each 1 pair of gold cuff links at $17.50 per pair. we have to find how much he pay

cost of 3 shirts if one cost at $8.50 is

cost of 2 dresses if one cost at $27.50 is  

cost of 1 pair of gold cuff at $17.50

so, total amount of money that he should pay if he has not used his duty free exemption is   $25.5+$55+$17.50=$98

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt