CAN SOMEONE PL HELPPP The figure below shows a shaded rectangular region inside a large rectangle:

A rectangle of length 10 units and width 5 units is shown. Inside this rectangle is a smaller rectangle of length 4 units and width 2 units placed symmetrically inside the larger rectangle. The smaller rectangle is shaded gray.

What is the probability that a point chosen inside the large rectangle is not in the shaded region?

8%
16%
50%
84%

84%

Step-by-step explanation:

The area of the large rectangle is 10 × 5 = 50.

The area of the small rectangle is 4 × 2 = 8.

The area of the large rectangle that isn't shaded is 50 − 8 = 42.

The fraction of the large rectangle that isn't shaded is 42 / 50 = 0.84.

Therefore, there is a 84% probability that a point chosen inside the large rectangle is not in the shaded region.

nope.   happens to me as well.

-aparri

h is the x-coordinate of the vertex

step-by-step explanation:

we have

in this function

the point represent the vertex of the function

so

h is the x-coordinate of the vertex

k is the y-coordinate of the vertex