A man usually rides his bike 9 kilometers per hour, yet the wind slows him to 6.76 kilometers for 26 minutes and 5.55 kilometers for 10, how long until he gets home 11.54 miles away?

It will take almost 2 hours 8 mins .

Step-by-step explanation:

The man rides his bicycle for 9 km for 1 hour.

He has to travel 11.54 miles.

1 mile = 1.609 km

11.54 miles= 11.54* 1.609 km= 18.568 = 18.57 km

It will take him 18.57 km / 9 km=  2.06 hrs= 127 mins

He moves 26 minutes at 6.76 km per hour meaning he moves 6.76/60 * 26=

2.93 km .

He moves 10 minutes at 5.55 km per hour meaning he moves 5.55/60 * 10=

0.925 km .

Out of 18.57 km he has moved 2.93+0.925= 3.855 km in 36 mins

18.57 km- 3.9 km =  14. 67 km is yet to travel

Now applying cross product rule

9 km                       60 mins

14.67 km                   ? x

x= 60 * 14.67/9= 97.8 mins

Total time taken will be 26 + 10 + 97.8 mins = 127.8 mins = 2 hours 7 mins

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

it would not be increasing by nothing that i can see probably by 25 percent that is all i can sat\y for now if i have any thing else to say i will edit this.

step-by-step explanation: