Roots in the question below x^4 +3x^2 -4=0

First, factor the equation.

The equation factors to...

(x+1)(x-1)(x^2+4) = 0

Set each term to 0.

x + 1 = 0

x = -1

x - 1 = 0

x = 1

x^2 + 4 = 0

x^2 = -4

Square root...

x = ±

x = 2i, -2i.

The 4 roots in the equation are -1, 1, 2i, and -2i.

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360 different combinations

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.