1. Evaluate uz + xy2 for u = 10, x = 3, y = 7, and z = 5
2. What is the value of xyz if x = −2, y = −6, and z = 4
3. Order the following numbers from least to greatest. 4710 4.1 − 5 √16
4. What is the simplified for of the following expression?
√ 181 14. Which statement about the product is true?
2.1 + 5.3
5. The product is irrational b. The product is neither rational nor irrational c. The nature of the product cannot be determined d. The product is rational 15. Which of the following results in a sum or product that is rational? Choose all that apply (3)
 π × 2  √7 + √3  1 + 3  1.24 × 2.7  √16 + √49
6. Which property is illustrates by the following statement?
7x(2) = (2)7x
7. Which property is illustrates by the following statement?
7x(2) = (2)7x

x = 12

y = 15

step-by-step explanation:

3/20

step-by-step explanation:

well, there are 20 outcomes, and 3 of them you want. so, 3/20

493 would be the correct answer

step-by-step explanation:

i think it's eleven too, don't woosh me here, but according to the "experts" it's 2.

the proof starts from the peano postulates, which define the natural

numbers n. n is the smallest set satisfying these postulates:

  p1.   1 is in n.

  p2.   if x is in n, then its "successor" x' is in n.

  p3.   there is no x such that x' = 1.

  p4.   if x isn't 1, then there is a y in n such that y' = x.

  p5.   if s is a subset of n, 1 is in s, and the implication

      (x in s => x' in s) holds, then s = n.

then you have to define addition recursively:

  def: let a and b be in n. if b = 1, then define a + b = a'

      (using p1 and p2). if b isn't 1, then let c' = b, with c in n

      (using p4), and define a + b = (a + c)'.

then you have to define 2:

  def:   2 = 1'

2 is in n by p1, p2, and the definition of 2.

theorem:   1 + 1 = 2

proof: use the first part of the definition of + with a = b = 1.

      then 1 + 1 = 1' = 2   q.e.d.

note: there is an alternate formulation of the peano postulates which

replaces 1 with 0 in p1, p3, p4, and p5. then you have to change the

definition of addition to this:

  def: let a and b be in n. if b = 0, then define a + b = a.

      if b isn't 0, then let c' = b, with c in n, and define

      a + b = (a + c)'.

you also have to define 1 = 0', and 2 = 1'. then the proof of the

theorem above is a little different:

proof: use the second part of the definition of + first:

      1 + 1 = (1 + 0)'

      now use the first part of the definition of + on the sum in

      parentheses:   1 + 1 = (1)' = 1' = 2   q.e.d.