Determine the common ratio and find the next three terms of the geometric sequence.
3 3 3
4' 10' 25'
a. 3 6 12 24
c. 2 6 12 24
5° 125° 625' 3125
5° 125 625 3125
b. 3 3 3 3
d. 2 3 3 3
5' 125' 625' 3125
5 125' 625' 3125

72 is the answer to this problem

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answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: